en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of 2cos(4x+pi/2)

Solution

inverse

2 cos (4 x + \frac{π}{2})

Solution

\frac{2 arccos ( \frac{x}{2} ) - π}{8}

Solution steps

Solve for

cos (4 x + \frac{π}{2}), y = 2 cos (4 x + \frac{π}{2})

cos (4 x + \frac{π}{2}) = \frac{y}{2}

cos (a) = b \Rightarrow a = arccos (b)

4 x + \frac{π}{2} = arccos (\frac{y}{2})

Solve for

x, 4 x + \frac{π}{2} = arccos (\frac{y}{2})

\frac{2 arccos ( \frac{y}{2} ) - π}{8}

Substitute

y = x

\frac{2 arccos ( \frac{x}{2} ) - π}{8}

Graph

Popular Examples

inverse of f(x)=(-9+2x)/3 inverse

f (x) = \frac{- 9 + 2 x}{3}

inverse of x^2-20x+5 inverse

x^{2} - 20 x + 5

inverse of f(x)=(2/3-8/3 x)/(2/3 x-8/3)inverse

f (x) = \frac{\frac{2}{3} - \frac{8}{3} x}{\frac{2}{3} x - \frac{8}{3}}

inverse of-(x-2)/4 inverse

- \frac{x - 2}{4}

inverse of y=5sqrt(x+3)inverse

y = 5 x + 3

Frequently Asked Questions (FAQ)

What is the inverse of 2cos(4x+pi/2) ?
The inverse of 2cos(4x+pi/2) is (2arccos(x/2)-pi)/8