What is the inverse of (sqrt(7+x))/(8-x) ?

The inverse of (sqrt(7+x))/(8-x) is (16x^2+1+sqrt(60x^2+1))/(2x^2),(16x^2+1-sqrt(60x^2+1))/(2x^2)

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inverse of (sqrt(7+x))/(8-x)

inverse

\frac{7 + x}{8 - x}

\frac{16 x ^{2} + 1 + 60 x ^{2} + 1}{2 x ^{2}}, \frac{16 x ^{2} + 1 - 60 x ^{2} + 1}{2 x ^{2}}

Solution steps

y = \frac{7 + x}{8 - x}

Replace

x

with

y

x = \frac{7 + y}{8 - y}

Solve for

y, x = \frac{7 + y}{8 - y}

\frac{16 x ^{2} + 1 + 60 x ^{2} + 1}{2 x ^{2}}, \frac{16 x ^{2} + 1 - 60 x ^{2} + 1}{2 x ^{2}}

f (x) = \frac{5 - 9 ( - 2 )}{( - 2 ) - 1}

f (x) = 7 (\frac{x - 1}{2})

f (x) = \frac{1}{x ^{2} + 3 x + 2}

f (x) = x^{2} + 2 {x er, x \geq 0}

f (x) = lo g_{10} (3)

What is the inverse of (sqrt(7+x))/(8-x) ?
The inverse of (sqrt(7+x))/(8-x) is (16x^2+1+sqrt(60x^2+1))/(2x^2),(16x^2+1-sqrt(60x^2+1))/(2x^2)