What is the f(x)=((3x^3+2x^2+5))/((x^2-4)) ?

The f(x)=((3x^3+2x^2+5))/((x^2-4)) is

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f(x)=((3x^3+2x^2+5))/((x^2-4))

f (x) = \frac{( 3 x ^{3} + 2 x ^{2} + 5 )}{( x ^{2} - 4 )}

Domain : x < - 2 or - 2 < x < 2 or x > 2

Range : - \infty < f (x) < \infty

X Intercepts : (- 1.45448 \dots, 0), Y Intercepts : (0, - \frac{5}{4})

Asymptotes : Vertical x = - 2, x = 2, Slant y = 3 x + 2

Extreme Points : Maximum (- 3.02193 \dots, - 11.59869 \dots), Minimum (- 0.75860 \dots, - 1.41370 \dots), Maximum (0, - \frac{5}{4}), Minimum (3.78053 \dots, 19.01240 \dots)

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{3 x ^{3} + 2 x ^{2} + 5}{x ^{2} - 4} : x < - 2 or - 2 < x < 2 or x > 2

Range of

\frac{3 x ^{3} + 2 x ^{2} + 5}{x ^{2} - 4} : - \infty < f (x) < \infty

Axis interception points of

\frac{3 x ^{3} + 2 x ^{2} + 5}{x ^{2} - 4} :

X Intercepts

: (- 1.45448 \dots, 0),

Y Intercepts

: (0, - \frac{5}{4})

Asymptotes of

\frac{3 x ^{3} + 2 x ^{2} + 5}{x ^{2} - 4} :

Vertical

: x = - 2, x = 2,

Slant

: y = 3 x + 2

Extreme Points of

\frac{3 x ^{3} + 2 x ^{2} + 5}{x ^{2} - 4} :

Maximum

(- 3.02193 \dots, - 11.59869 \dots),

Minimum

(- 0.75860 \dots, - 1.41370 \dots),

Maximum

(0, - \frac{5}{4}),

Minimum

(3.78053 \dots, 19.01240 \dots)

- x - 5

f (x) = \frac{3 x}{x + 4}

f (x) = 7 x^{7}

f (x) = \frac{x + 10}{x - 4}

f (x) = 4 x - 2 x^{3} - 5

What is the f(x)=((3x^3+2x^2+5))/((x^2-4)) ?
The f(x)=((3x^3+2x^2+5))/((x^2-4)) is