What is the inverse of (1-2x^3)/(x^3) ?

The inverse of (1-2x^3)/(x^3) is cube root of 1/(x+2)

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inverse of (1-2x^3)/(x^3)

inverse

\frac{1 - 2 x ^{3}}{x ^{3}}

3 \frac{1}{x + 2}

Solution steps

y = \frac{1 - 2 x ^{3}}{x ^{3}}

Replace

x

with

y

x = \frac{1 - 2 y ^{3}}{y ^{3}}

Solve for

y, x = \frac{1 - 2 y ^{3}}{y ^{3}}

3 \frac{1}{x + 2}

f (x) = - (x + 5)^{2} + 33

f (x) = \frac{7 x}{( 3 x - 1 )}

\frac{t ^{2} + 1}{t - 1}

\frac{1}{3 x + 4}

f (x) = \frac{e ^{x} - 3}{2 - e ^{x}}

What is the inverse of (1-2x^3)/(x^3) ?
The inverse of (1-2x^3)/(x^3) is cube root of 1/(x+2)