What is the inverse of f(x)=\sqrt[3]{x+9}+2 ?

The inverse of f(x)=\sqrt[3]{x+9}+2 is x^3-6x^2+12x-17

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inverse of f(x)=\sqrt[3]{x+9}+2

inverse

f (x) = 3 x + 9 + 2

x^{3} - 6 x^{2} + 12 x - 17

Solution steps

y = 3 x + 9 + 2

Replace

x

with

y

x = 3 y + 9 + 2

Solve for

y, x = 3 y + 9 + 2

x^{3} - 6 x^{2} + 12 x - 17

f (x) = - \frac{x - 2}{2 x - 6}

f (x) = 3 + 2 x - 5

\frac{( x + 3 )}{x + 11}

f (x) = 11.25 x + 90

f (x) = \frac{4 x - 6}{2}

What is the inverse of f(x)=\sqrt[3]{x+9}+2 ?
The inverse of f(x)=\sqrt[3]{x+9}+2 is x^3-6x^2+12x-17