What is the inverse of f(x)=5x^2 1/2 ?

The inverse of f(x)=5x^2 1/2 is sqrt((2x)/5),-sqrt((2x)/5)

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inverse of f(x)=5x^2 1/2

inverse

f (x) = 5 x^{2} \frac{1}{2}

\frac{2 x}{5}, - \frac{2 x}{5}

Solution steps

y = 5 x^{2} \frac{1}{2}

Replace

x

with

y

x = 5 y^{2} \frac{1}{2}

Solve for

y, x = 5 y^{2} \frac{1}{2}

\frac{2 x}{5}, - \frac{2 x}{5}

13 - x

f (x) = lo g_{10} (7^{x})

f (x) = 2 x - 2 + 3

\frac{x ^{2}}{x + 2}

y = 5 x + 1

What is the inverse of f(x)=5x^2 1/2 ?
The inverse of f(x)=5x^2 1/2 is sqrt((2x)/5),-sqrt((2x)/5)