What is the inverse of \sqrt[5]{x-2}-2 ?

The inverse of \sqrt[5]{x-2}-2 is x^5+10x^4+40x^3+80x^2+80x+34

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inverse of \sqrt[5]{x-2}-2

inverse

5 x - 2 - 2

x^{5} + 10 x^{4} + 40 x^{3} + 80 x^{2} + 80 x + 34

Solution steps

y = 5 x - 2 - 2

Replace

x

with

y

x = 5 y - 2 - 2

Solve for

y, x = 5 y - 2 - 2

x^{5} + 10 x^{4} + 40 x^{3} + 80 x^{2} + 80 x + 34

f (x) = 3 - 3 - 2 2^{- 1}

10.7 + 3 x - 4

f (x) = (x + 1)

arccsc (\frac{5}{3})

f (x) = lo g_{3} (x) + 8

What is the inverse of \sqrt[5]{x-2}-2 ?
The inverse of \sqrt[5]{x-2}-2 is x^5+10x^4+40x^3+80x^2+80x+34