What is the inverse of f(x)=2x^2+3x+4 ?

The inverse of f(x)=2x^2+3x+4 is (-3+sqrt(8x-23))/4 ,(-3-sqrt(8x-23))/4

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inverse of f(x)=2x^2+3x+4

inverse

f (x) = 2 x^{2} + 3 x + 4

\frac{- 3 + 8 x - 23}{4}, \frac{- 3 - 8 x - 23}{4}

Solution steps

y = 2 x^{2} + 3 x + 4

Replace

x

with

y

x = 2 y^{2} + 3 y + 4

Solve for

y, x = 2 y^{2} + 3 y + 4

\frac{- 3 + 8 x - 23}{4}, \frac{- 3 - 8 x - 23}{4}

g (x) = 6 cos (x) - 3

f (x) = 1.323

f (x) = \frac{4}{2}

4 x - 1

f (x) = arcsin (x - 1)

What is the inverse of f(x)=2x^2+3x+4 ?
The inverse of f(x)=2x^2+3x+4 is (-3+sqrt(8x-23))/4 ,(-3-sqrt(8x-23))/4