What is the inverse of (-2s+6)/(s^2+4) ?

The inverse of (-2s+6)/(s^2+4) is (-1+sqrt(-2s(2s-3)+1))/s ,-(sqrt(-2s(2s-3)+1)+1)/s

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inverse of (-2s+6)/(s^2+4)

inverse

\frac{- 2 s + 6}{s ^{2} + 4}

\frac{- 1 + - 2 s ( 2 s - 3 ) + 1}{s}, - \frac{- 2 s ( 2 s - 3 ) + 1 + 1}{s}

Solution steps

y = \frac{- 2 s + 6}{s ^{2} + 4}

Replace

s

with

y

s = \frac{- 2 y + 6}{y ^{2} + 4}

Solve for

y, s = \frac{- 2 y + 6}{y ^{2} + 4}

\frac{- 1 + - 2 s ( 2 s - 3 ) + 1}{s}, - \frac{- 2 s ( 2 s - 3 ) + 1 + 1}{s}

lo g_{10} (x + 3) + 5

y = 1 + ln (x + 4)

e^{x} + 10

f (x) = \frac{x - 6}{1 + 4 x}

f (x) = x^{2} - 4 x - 32

What is the inverse of (-2s+6)/(s^2+4) ?
The inverse of (-2s+6)/(s^2+4) is (-1+sqrt(-2s(2s-3)+1))/s ,-(sqrt(-2s(2s-3)+1)+1)/s