What is the inverse of f(x)=21t^{0.8} ?

The inverse of f(x)=21t^{0.8} is (21^{3/4}t\sqrt[4]{t})/(441),-(21^{3/4}t\sqrt[4]{t})/(441)

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inverse of f(x)=21t^{0.8}

inverse

f (x) = 21 t^{0.8}

\frac{2 1 ^{\frac{3}{4}} t 4 t}{441}, - \frac{2 1 ^{\frac{3}{4}} t 4 t}{441}

Solution steps

x = 21 t^{0.8}

Replace

t

with

x

t = 21 x^{0.8}

Solve for

x, t = 21 x^{0.8}

\frac{2 1 ^{\frac{3}{4}} t 4 t}{441}, - \frac{2 1 ^{\frac{3}{4}} t 4 t}{441}

5 + 3 x - 4

y = e^{7 - 6 x}

f (x) = 6.75 x + 12

5 - x^{2}, x \geq 0

f (x) = (x - 4)^{2} - 1, x \geq 4

What is the inverse of f(x)=21t^{0.8} ?
The inverse of f(x)=21t^{0.8} is (21^{3/4}t\sqrt[4]{t})/(441),-(21^{3/4}t\sqrt[4]{t})/(441)