What is the inverse of f(x)=x^2-4x-16 ?

The inverse of f(x)=x^2-4x-16 is 2+sqrt(x+20),2-sqrt(x+20)

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inverse of f(x)=x^2-4x-16

inverse

f (x) = x^{2} - 4 x - 16

2 + x + 20, 2 - x + 20

Solution steps

y = x^{2} - 4 x - 16

Replace

x

with

y

x = y^{2} - 4 y - 16

Solve for

y, x = y^{2} - 4 y - 16

2 + x + 20, 2 - x + 20

lo g_{6} (4 x + 4)

f (x) = \frac{- 4 x + 1}{9 + 5 x}

f (x) = \frac{4 x - 2}{4 x}

\frac{4 - 3 x}{4 x - 2}

f (s) = \frac{6}{8} - \frac{1}{s - 8} + \frac{4}{s - 3}

What is the inverse of f(x)=x^2-4x-16 ?
The inverse of f(x)=x^2-4x-16 is 2+sqrt(x+20),2-sqrt(x+20)