What is the inverse of f(x)=((7x-1))/((3x+5)) ?

The inverse of f(x)=((7x-1))/((3x+5)) is (-1-5x)/(3x-7)

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inverse of f(x)=((7x-1))/((3x+5))

inverse

f (x) = \frac{( 7 x - 1 )}{( 3 x + 5 )}

\frac{- 1 - 5 x}{3 x - 7}

Solution steps

y = \frac{7 x - 1}{3 x + 5}

Replace

x

with

y

x = \frac{7 y - 1}{3 y + 5}

Solve for

y, x = \frac{7 y - 1}{3 y + 5}

\frac{- 1 - 5 x}{3 x - 7}

y = \frac{1}{2} arccos (x)

f (x) = - 20

f (x) = \frac{x}{( x - 1 ) ^{2}}

f (x) = 5 e^{- x} - 2

f (x) = \frac{3 - 7 x}{4 + 5 x}

What is the inverse of f(x)=((7x-1))/((3x+5)) ?
The inverse of f(x)=((7x-1))/((3x+5)) is (-1-5x)/(3x-7)