What is the inverse of f(x)=20ln(40t-1200) ?

The inverse of f(x)=20ln(40t-1200) is (e^{t/(20)}+1200)/(40)

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inverse of f(x)=20ln(40t-1200)

inverse

f (x) = 20 ln (40 t - 1200)

\frac{e ^{\frac{t}{20}} + 1200}{40}

Solution steps

x = 20 ln (40 t - 1200)

Replace

t

with

x

t = 20 ln (40 x - 1200)

Solve for

x, t = 20 ln (40 x - 1200)

\frac{e ^{\frac{t}{20}} + 1200}{40}

f (x) = \frac{4 x}{3 x - 5}

+ cot (x)

3 X + 7

f (x) = \frac{2}{y - 4} + 3

2 x - 3 b

What is the inverse of f(x)=20ln(40t-1200) ?
The inverse of f(x)=20ln(40t-1200) is (e^{t/(20)}+1200)/(40)