What is the inverse of (x^2)/(x+7) ?

The inverse of (x^2)/(x+7) is (x+sqrt(x^2+28x))/2 ,(x-sqrt(x^2+28x))/2

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inverse of (x^2)/(x+7)

inverse

\frac{x ^{2}}{x + 7}

\frac{x + x ^{2} + 28 x}{2}, \frac{x - x ^{2} + 28 x}{2}

Solution steps

y = \frac{x ^{2}}{x + 7}

Replace

x

with

y

x = \frac{y ^{2}}{y + 7}

Solve for

y, x = \frac{y ^{2}}{y + 7}

\frac{x + x ^{2} + 28 x}{2}, \frac{x - x ^{2} + 28 x}{2}

3. 2^{x}

- 2 x^{2} + 4

h (x) = e^{4 x + 1} - 2

\frac{- 4 x + 4}{- 2 x + 1}

y = lo g_{3} (81) x

What is the inverse of (x^2)/(x+7) ?
The inverse of (x^2)/(x+7) is (x+sqrt(x^2+28x))/2 ,(x-sqrt(x^2+28x))/2