What is the inverse of (2s+1)/(s^2-2s-2) ?

The inverse of (2s+1)/(s^2-2s-2) is (s+1+sqrt(3s^2+3s+1))/s ,(s+1-sqrt(3s^2+3s+1))/s

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inverse of (2s+1)/(s^2-2s-2)

inverse

\frac{2 s + 1}{s ^{2} - 2 s - 2}

\frac{s + 1 + 3 s ^{2} + 3 s + 1}{s}, \frac{s + 1 - 3 s ^{2} + 3 s + 1}{s}

Solution steps

y = \frac{2 s + 1}{s ^{2} - 2 s - 2}

Replace

s

with

y

s = \frac{2 y + 1}{y ^{2} - 2 y - 2}

Solve for

y, s = \frac{2 y + 1}{y ^{2} - 2 y - 2}

\frac{s + 1 + 3 s ^{2} + 3 s + 1}{s}, \frac{s + 1 - 3 s ^{2} + 3 s + 1}{s}

ln (4 - 2 x)

f (x) = f (x) = 49 - x^{2}

f (x) = f (x) = 6 x - 5

\frac{- 4 x}{7}

f (4) = - 2 x + 5

What is the inverse of (2s+1)/(s^2-2s-2) ?
The inverse of (2s+1)/(s^2-2s-2) is (s+1+sqrt(3s^2+3s+1))/s ,(s+1-sqrt(3s^2+3s+1))/s