What is the inverse of 3/(sqrt(9-x^2)) ?

The inverse of 3/(sqrt(9-x^2)) is sqrt(-(9-9x^2)/(x^2)),-sqrt(-(9-9x^2)/(x^2))

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inverse of 3/(sqrt(9-x^2))

inverse

\frac{3}{9 - x ^{2}}

- \frac{9 - 9 x ^{2}}{x ^{2}}, - - \frac{9 - 9 x ^{2}}{x ^{2}}

Solution steps

y = \frac{3}{9 - x ^{2}}

Replace

x

with

y

x = \frac{3}{9 - y ^{2}}

Solve for

y, x = \frac{3}{9 - y ^{2}}

- \frac{9 - 9 x ^{2}}{x ^{2}}, - - \frac{9 - 9 x ^{2}}{x ^{2}}

f (x) = 20 x + 5

f (x) = 6 x - 52

f (x) = 2 x + 0

f (x) = lo g_{10} (x) + 5

f (x) = - 4 - \frac{4}{3}

What is the inverse of 3/(sqrt(9-x^2)) ?
The inverse of 3/(sqrt(9-x^2)) is sqrt(-(9-9x^2)/(x^2)),-sqrt(-(9-9x^2)/(x^2))