What is the inverse of f(x)=(-10x+1)^2 ?

The inverse of f(x)=(-10x+1)^2 is -(sqrt(x)-1)/(10),-(-sqrt(x)-1)/(10)

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inverse of f(x)=(-10x+1)^2

inverse

f (x) = (- 10 x + 1)^{2}

- \frac{x - 1}{10}, - \frac{- x - 1}{10}

Solution steps

y = (- 10 x + 1)^{2}

Replace

x

with

y

x = (- 10 y + 1)^{2}

Solve for

y, x = (- 10 y + 1)^{2}

- \frac{x - 1}{10}, - \frac{- x - 1}{10}

f (x) = \frac{2 x - 5}{4 x - 1} + 3

\frac{s - 5}{( s + 3 ) ( s - 2 )}

f (x) = - 6 x^{5} + 8

y = 2^{x - 3} - 5

f (x) = \frac{5 y + 1}{2 - 5 y}

What is the inverse of f(x)=(-10x+1)^2 ?
The inverse of f(x)=(-10x+1)^2 is -(sqrt(x)-1)/(10),-(-sqrt(x)-1)/(10)