What is the inverse of g(x)= 0/(2^{x+1)} ?

The inverse of g(x)= 0/(2^{x+1)} is None

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inverse of g(x)= 0/(2^{x+1)}

inverse

g (x) = \frac{0}{2 ^{x + 1}}

None

Solution steps

y = \frac{0}{2 ^{x + 1}}

Replace

x

with

y

x = \frac{0}{2 ^{y + 1}}

Solve for

y, x = \frac{0}{2 ^{y + 1}}

Therefore, there are no inverse functions for

\frac{0}{2 ^{x + 1}}

None

f (x) = 6^{3 + 2 x}

y = - 0.1 x + 14

1 + ln (x)

f (x) = \frac{6 x - 6}{5 x + 1}

f (x) = \frac{75 ( x )}{85 - x}

What is the inverse of g(x)= 0/(2^{x+1)} ?
The inverse of g(x)= 0/(2^{x+1)} is None