What is the inverse of (2(x-3)(x-1))/((x-3)(x+3)) ?

The inverse of (2(x-3)(x-1))/((x-3)(x+3)) is (-2-3x)/(x-2)

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inverse of (2(x-3)(x-1))/((x-3)(x+3))

inverse

\frac{2 ( x - 3 ) ( x - 1 )}{( x - 3 ) ( x + 3 )}

\frac{- 2 - 3 x}{x - 2}

Solution steps

y = \frac{2 ( x - 3 ) ( x - 1 )}{( x - 3 ) ( x + 3 )}

Replace

x

with

y

x = \frac{2 ( y - 3 ) ( y - 1 )}{( y - 3 ) ( y + 3 )}

Solve for

y, x = \frac{2 ( y - 3 ) ( y - 1 )}{( y - 3 ) ( y + 3 )}

\frac{- 2 - 3 x}{x - 2}

f (x) = \frac{21 x}{12} - 13

e^{(x + 3)} + 3

\frac{1}{k - s}

f (x) = 8 + 5 x - 9

f (x) = \frac{2}{12 + 3 x}

What is the inverse of (2(x-3)(x-1))/((x-3)(x+3)) ?
The inverse of (2(x-3)(x-1))/((x-3)(x+3)) is (-2-3x)/(x-2)