What is the inverse of 1/2*\sqrt[3]{-3x-8} ?

The inverse of 1/2*\sqrt[3]{-3x-8} is -(8x^3+8)/3

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inverse of 1/2*\sqrt[3]{-3x-8}

inverse

- \frac{8 x ^{3} + 8}{3}

Solution steps

Replace

x

with

y

Solve for

- \frac{8 x ^{3} + 8}{3}

f (x) = 17 - 4 x

f (x) = 4.2435 x + 169.43

f (x) = \frac{x}{7} + 3

f (x) = \frac{( 3 - 2 x )}{2 x - 5}

h (x) = \frac{x - 1}{3}

What is the inverse of 1/2*\sqrt[3]{-3x-8} ?
The inverse of 1/2*\sqrt[3]{-3x-8} is -(8x^3+8)/3