What is the inverse of y=sin^2(x) ?

The inverse of y=sin^2(x) is arcsin(sqrt(x)),arcsin(-sqrt(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y=sin^2(x)

inverse

y = sin^{2} (x)

arcsin (x), arcsin (- x)

Solution steps

Solve for

sin (x), y = sin^{2} (x)

sin (x) = y, sin (x) = - y

sin (a) = b \Rightarrow a = arcsin (b)

arcsin (y), arcsin (- y)

Substitute

y = x

arcsin (x), arcsin (- x)

f (x) = (0.1)

f (x) = (x + 6)^{2} - 5

f (x) = (x + 6)^{2} - 4

f (x) = - \frac{31 x}{8} - 9

f (x) = - x^{2} - 8 x + 7

What is the inverse of y=sin^2(x) ?
The inverse of y=sin^2(x) is arcsin(sqrt(x)),arcsin(-sqrt(x))