What is the inverse of f(x)=-2(x-4)^2+1 ?

The inverse of f(x)=-2(x-4)^2+1 is sqrt(-(x-1)/2)+4,-sqrt(-(x-1)/2)+4

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inverse of f(x)=-2(x-4)^2+1

inverse

f (x) = - 2 (x - 4)^{2} + 1

- \frac{x - 1}{2} + 4, - - \frac{x - 1}{2} + 4

Solution steps

y = - 2 (x - 4)^{2} + 1

Replace

x

with

y

x = - 2 (y - 4)^{2} + 1

Solve for

y, x = - 2 (y - 4)^{2} + 1

- \frac{x - 1}{2} + 4, - - \frac{x - 1}{2} + 4

tan (\frac{6}{7})

f (x) = 19 x + 4

arctan (0)

f (x) = \frac{( - 2 x - 8 )}{3}

sin (x) 0.902

What is the inverse of f(x)=-2(x-4)^2+1 ?
The inverse of f(x)=-2(x-4)^2+1 is sqrt(-(x-1)/2)+4,-sqrt(-(x-1)/2)+4