What is the inverse of f(x)=(((7x))/((8x-1))) ?

The inverse of f(x)=(((7x))/((8x-1))) is x/(8x-7)

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inverse of f(x)=(((7x))/((8x-1)))

inverse

f (x) = (\frac{( 7 x )}{( 8 x - 1 )})

\frac{x}{8 x - 7}

Solution steps

y = \frac{7 x}{8 x - 1}

Replace

x

with

y

x = \frac{7 y}{8 y - 1}

Solve for

y, x = \frac{7 y}{8 y - 1}

\frac{x}{8 x - 7}

f (x) = 2 y - 5

f (x) = y^{2} - 2 y

\frac{3 x}{4 x - 1}

3 (x - 2)^{3} + 1

What is the inverse of f(x)=(((7x))/((8x-1))) ?
The inverse of f(x)=(((7x))/((8x-1))) is x/(8x-7)