What is the inverse of y(b)=(-b^2)/(-4+b^2) ?

The inverse of y(b)=(-b^2)/(-4+b^2) is (2sqrt(b)sqrt(b+1))/(b+1),-(2sqrt(b)sqrt(b+1))/(b+1)

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inverse of y(b)=(-b^2)/(-4+b^2)

inverse

y (b) = \frac{- b ^{2}}{- 4 + b ^{2}}

\frac{2 b b + 1}{b + 1}, - \frac{2 b b + 1}{b + 1}

Solution steps

y = \frac{- b ^{2}}{- 4 + b ^{2}}

Replace

b

with

y

b = \frac{- y ^{2}}{- 4 + y ^{2}}

Solve for

y, b = \frac{- y ^{2}}{- 4 + y ^{2}}

\frac{2 b b + 1}{b + 1}, - \frac{2 b b + 1}{b + 1}

a^{4} - 2 a^{2} + 9

f (x) = \frac{3 x + 5}{x + 3}

f (x) = 2 (- 2 x - 5)^{2} - 4, x \geq - \frac{5}{2}

y = (1 + x) (5 - x)

What is the inverse of y(b)=(-b^2)/(-4+b^2) ?
The inverse of y(b)=(-b^2)/(-4+b^2) is (2sqrt(b)sqrt(b+1))/(b+1),-(2sqrt(b)sqrt(b+1))/(b+1)