What is the inverse of 2/s-2/(s+1) ?

The inverse of 2/s-2/(s+1) is (-s+sqrt(s^2+8s))/(2s),(-s-sqrt(s^2+8s))/(2s)

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inverse of 2/s-2/(s+1)

inverse

\frac{2}{s} - \frac{2}{s + 1}

\frac{- s + s ^{2} + 8 s}{2 s}, \frac{- s - s ^{2} + 8 s}{2 s}

Solution steps

y = \frac{2}{s} - \frac{2}{s + 1}

Replace

s

with

y

s = \frac{2}{y} - \frac{2}{y + 1}

Solve for

y, s = \frac{2}{y} - \frac{2}{y + 1}

\frac{- s + s ^{2} + 8 s}{2 s}, \frac{- s - s ^{2} + 8 s}{2 s}

f (x) = - 2^{x + 1} + 4

f (x) = 4 x - \frac{7}{8}

f (x) = ln (x^{2} + 2 x + 2)

f (x) = \frac{( ( x + 3 ) )}{( ( x - 2 ) )}

What is the inverse of 2/s-2/(s+1) ?
The inverse of 2/s-2/(s+1) is (-s+sqrt(s^2+8s))/(2s),(-s-sqrt(s^2+8s))/(2s)