What is the inverse of (2x^2-3)/(x^2+2x+1) ?

The inverse of (2x^2-3)/(x^2+2x+1) is (-x+sqrt(-x+6))/(x-2),-(x+sqrt(-x+6))/(x-2)

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inverse of (2x^2-3)/(x^2+2x+1)

inverse

\frac{2 x ^{2} - 3}{x ^{2} + 2 x + 1}

\frac{- x + - x + 6}{x - 2}, - \frac{x + - x + 6}{x - 2}

Solution steps

y = \frac{2 x ^{2} - 3}{x ^{2} + 2 x + 1}

Replace

x

with

y

x = \frac{2 y ^{2} - 3}{y ^{2} + 2 y + 1}

Solve for

y, x = \frac{2 y ^{2} - 3}{y ^{2} + 2 y + 1}

\frac{- x + - x + 6}{x - 2}, - \frac{x + - x + 6}{x - 2}

y = \frac{4}{x + 2} + 8

f (x) = 4 x^{2} - 2, x \geq 0

f (x) = \frac{A}{x}

f (x) = - \frac{x}{3}

What is the inverse of (2x^2-3)/(x^2+2x+1) ?
The inverse of (2x^2-3)/(x^2+2x+1) is (-x+sqrt(-x+6))/(x-2),-(x+sqrt(-x+6))/(x-2)