What is the inverse of-x/(x^2-9) ?

The inverse of-x/(x^2-9) is (-1+sqrt(1+36x^2))/(2x),(-1-sqrt(1+36x^2))/(2x)

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inverse of-x/(x^2-9)

inverse

- \frac{x}{x ^{2} - 9}

\frac{- 1 + 1 + 36 x ^{2}}{2 x}, \frac{- 1 - 1 + 36 x ^{2}}{2 x}

Solution steps

y = - \frac{x}{x ^{2} - 9}

Replace

x

with

y

x = - \frac{y}{y ^{2} - 9}

Solve for

y, x = - \frac{y}{y ^{2} - 9}

\frac{- 1 + 1 + 36 x ^{2}}{2 x}, \frac{- 1 - 1 + 36 x ^{2}}{2 x}

f (x) = (5 x + 1)^{\frac{1}{3}}

f (x) = \frac{4 - 5 x}{2}

f (x) = e^{\frac{x}{4.49}}

f (x) = - 0.5 x^{2} - 2

f (x) = 5 x_{1}

What is the inverse of-x/(x^2-9) ?
The inverse of-x/(x^2-9) is (-1+sqrt(1+36x^2))/(2x),(-1-sqrt(1+36x^2))/(2x)