What is the inverse of f(x)=log_{9}((x+3)/2)-1 ?

The inverse of f(x)=log_{9}((x+3)/2)-1 is 9^{x+1}*2-3

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inverse of f(x)=log_{9}((x+3)/2)-1

inverse

f (x) = lo g_{9} (\frac{x + 3}{2}) - 1

9^{x + 1} \cdot 2 - 3

Solution steps

y = lo g_{9} (\frac{x + 3}{2}) - 1

Replace

x

with

y

x = lo g_{9} (\frac{y + 3}{2}) - 1

Solve for

y, x = lo g_{9} (\frac{y + 3}{2}) - 1

9^{x + 1} \cdot 2 - 3

f (x) = x^{3} y = - 8

\frac{5 x + 7}{2 x - 5}

f (x) = y - 1 + 4

f (x) = arccos (\frac{2}{2})

f (x) = 1.02 x

What is the inverse of f(x)=log_{9}((x+3)/2)-1 ?
The inverse of f(x)=log_{9}((x+3)/2)-1 is 9^{x+1}*2-3