What is the inverse of-2x^2+8x-4 ?

The inverse of-2x^2+8x-4 is -(-8+sqrt(-8x+32))/4 ,-(-8-sqrt(-8x+32))/4

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inverse of-2x^2+8x-4

inverse

- 2 x^{2} + 8 x - 4

- \frac{- 8 + - 8 x + 32}{4}, - \frac{- 8 - - 8 x + 32}{4}

Solution steps

y = - 2 x^{2} + 8 x - 4

Replace

x

with

y

x = - 2 y^{2} + 8 y - 4

Solve for

y, x = - 2 y^{2} + 8 y - 4

- \frac{- 8 + - 8 x + 32}{4}, - \frac{- 8 - - 8 x + 32}{4}

(1 + n) u (n)

f (x) = f (x) = - \frac{5}{3} x - 5

g (x) = 36 x^{2}

F (s) = 2 s (s 4 + 24 s 2 + 144)

arccot (- 1)

What is the inverse of-2x^2+8x-4 ?
The inverse of-2x^2+8x-4 is -(-8+sqrt(-8x+32))/4 ,-(-8-sqrt(-8x+32))/4