What is the inverse of f(x)=y^2-8y ?

The inverse of f(x)=y^2-8y is 4+sqrt(y+16),4-sqrt(y+16)

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inverse of f(x)=y^2-8y

inverse

f (x) = y^{2} - 8 y

4 + y + 16, 4 - y + 16

Solution steps

x = y^{2} - 8 y

Replace

y

with

x

y = x^{2} - 8 x

Solve for

x, y = x^{2} - 8 x

4 + y + 16, 4 - y + 16

cos (100 f)

f (\frac{x + 2020}{x + 2022}) = x + 2021

\frac{4 x ^{2} + 5}{6 x + 4}

e^{5 x + 2} + 3

e^{5 x + 2} + 5

What is the inverse of f(x)=y^2-8y ?
The inverse of f(x)=y^2-8y is 4+sqrt(y+16),4-sqrt(y+16)