What is the inverse of f(x)=-2(x+1)^{2+3} ?

The inverse of f(x)=-2(x+1)^{2+3} is -\sqrt[5]{x/2}-1

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inverse of f(x)=-2(x+1)^{2+3}

inverse

f (x) = - 2 (x + 1)^{2 + 3}

Solution steps

y = - 2 (x + 1)^{2 + 3}

Replace

x

with

y

x = - 2 (y + 1)^{2 + 3}

Solve for

y, x = - 2 (y + 1)^{2 + 3}

\frac{3 x}{x ^{2} - 9}

f (h) = 45 - 1.25 h

2^{x} + 1

cos (\frac{677}{36960})

2 x^{2} - 5 x - 2

What is the inverse of f(x)=-2(x+1)^{2+3} ?
The inverse of f(x)=-2(x+1)^{2+3} is -\sqrt[5]{x/2}-1