What is the inverse of (x^{2/3})/(x^{9/4)} ?

The inverse of (x^{2/3})/(x^{9/4)} is (1/x)^{12/19}

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inverse of (x^{2/3})/(x^{9/4)}

inverse

\frac{x ^{\frac{2}{3}}}{x ^{\frac{9}{4}}}

(\frac{1}{x})^{\frac{12}{19}}

Solution steps

y = \frac{x ^{\frac{2}{3}}}{x ^{\frac{9}{4}}}

Replace

x

with

y

x = \frac{y ^{\frac{2}{3}}}{y ^{\frac{9}{4}}}

Solve for

y, x = \frac{y ^{\frac{2}{3}}}{y ^{\frac{9}{4}}}

(\frac{1}{x})^{\frac{12}{19}}

y = lo g_{e} (x - 2)

2 x^{2} - 5 x + 1

f (x) = \frac{2 e ^{5 x} - 6}{5 e ^{5 x} + 2}

f (x) = \frac{5}{x ^{4}}

y = 9 x + 6

What is the inverse of (x^{2/3})/(x^{9/4)} ?
The inverse of (x^{2/3})/(x^{9/4)} is (1/x)^{12/19}