What is the inverse of 4/(2x^2-11x+5) ?

The inverse of 4/(2x^2-11x+5) is (11x+sqrt(81x^2+32x))/(4x),(11x-sqrt(81x^2+32x))/(4x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of 4/(2x^2-11x+5)

inverse

\frac{4}{2 x ^{2} - 11 x + 5}

\frac{11 x + 81 x ^{2} + 32 x}{4 x}, \frac{11 x - 81 x ^{2} + 32 x}{4 x}

Solution steps

y = \frac{4}{2 x ^{2} - 11 x + 5}

Replace

x

with

y

x = \frac{4}{2 y ^{2} - 11 y + 5}

Solve for

y, x = \frac{4}{2 y ^{2} - 11 y + 5}

\frac{11 x + 81 x ^{2} + 32 x}{4 x}, \frac{11 x - 81 x ^{2} + 32 x}{4 x}

2 x - 8

- \frac{x - 1}{3} - 2

f (x) = 6 \cdot x \cdot (x - 1) + 1

f (x) = 2 x^{\frac{1}{5}} - 5

cos (x) - 1

What is the inverse of 4/(2x^2-11x+5) ?
The inverse of 4/(2x^2-11x+5) is (11x+sqrt(81x^2+32x))/(4x),(11x-sqrt(81x^2+32x))/(4x)