What is the inverse of f(x)=(4x-2)/(3x-1) ?

The inverse of f(x)=(4x-2)/(3x-1) is (-2+x)/(3x-4)

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inverse of f(x)=(4x-2)/(3x-1)

inverse

f (x) = \frac{4 x - 2}{3 x - 1}

\frac{- 2 + x}{3 x - 4}

Solution steps

y = \frac{4 x - 2}{3 x - 1}

Replace

x

with

y

x = \frac{4 y - 2}{3 y - 1}

Solve for

y, x = \frac{4 y - 2}{3 y - 1}

\frac{- 2 + x}{3 x - 4}

10 ln (tan (x))

f (x) = 2 x^{\frac{1}{5}} + 3

y = 9 x - 4

y = 9 x - 8

f (x) = \frac{x + 1}{6}

What is the inverse of f(x)=(4x-2)/(3x-1) ?
The inverse of f(x)=(4x-2)/(3x-1) is (-2+x)/(3x-4)