What is the inverse of f(x)=(2x-1)/((x+1)) ?

The inverse of f(x)=(2x-1)/((x+1)) is (-1-x)/(x-2)

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inverse of f(x)=(2x-1)/((x+1))

inverse

f (x) = \frac{2 x - 1}{( x + 1 )}

\frac{- 1 - x}{x - 2}

Solution steps

y = \frac{2 x - 1}{x + 1}

Replace

x

with

y

x = \frac{2 y - 1}{y + 1}

Solve for

y, x = \frac{2 y - 1}{y + 1}

\frac{- 1 - x}{x - 2}

f (x) = - 8.4 x + 378

\frac{8 x}{3 x - 2}

f (x) = \frac{1}{1 - a}

f (x) = 16 (x^{4} - x^{2})

lo g_{10} (\frac{X}{1 0 ^{- 16}})

What is the inverse of f(x)=(2x-1)/((x+1)) ?
The inverse of f(x)=(2x-1)/((x+1)) is (-1-x)/(x-2)