What is the inverse of f(x)= y/4-(y^2)/2-1/8 ?

The inverse of f(x)= y/4-(y^2)/2-1/8 is -(-1+sqrt(-32y-3))/4 ,(sqrt(-32y-3)+1)/4

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inverse of f(x)= y/4-(y^2)/2-1/8

inverse

f (x) = \frac{y}{4} - \frac{y ^{2}}{2} - \frac{1}{8}

- \frac{- 1 + - 32 y - 3}{4}, \frac{- 32 y - 3 + 1}{4}

Solution steps

x = \frac{y}{4} - \frac{y ^{2}}{2} - \frac{1}{8}

Replace

y

with

x

y = \frac{x}{4} - \frac{x ^{2}}{2} - \frac{1}{8}

Solve for

x, y = \frac{x}{4} - \frac{x ^{2}}{2} - \frac{1}{8}

- \frac{- 1 + - 32 y - 3}{4}, \frac{- 32 y - 3 + 1}{4}

\frac{e ^{x} - 6}{5 - e ^{x}}

\frac{1 - 3 x}{2 x + 1}

f (x) = \frac{- 3 x + 6}{4 x + 9}

\frac{2 x + 1}{x - 4}

f (x) = 32145

What is the inverse of f(x)= y/4-(y^2)/2-1/8 ?
The inverse of f(x)= y/4-(y^2)/2-1/8 is -(-1+sqrt(-32y-3))/4 ,(sqrt(-32y-3)+1)/4