What is the inverse of sqrt(4k^2+16k+25) ?

The inverse of sqrt(4k^2+16k+25) is (-4+sqrt(k^2-9))/2 ,-(sqrt(k^2-9)+4)/2

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inverse of sqrt(4k^2+16k+25)

inverse

4 k^{2} + 16 k + 25

\frac{- 4 + k ^{2} - 9}{2}, - \frac{k ^{2} - 9 + 4}{2}

Solution steps

y = 4 k^{2} + 16 k + 25

Replace

k

with

y

k = 4 y^{2} + 16 y + 25

Solve for

y, k = 4 y^{2} + 16 y + 25

\frac{- 4 + k ^{2} - 9}{2}, - \frac{k ^{2} - 9 + 4}{2}

9^{x} + 2 \cdot 3^{x} + 3, x \leq 0

\frac{8 x}{3 x - 5}

f (x) = (x^{8} - 9)

f (x) = 4 x - 5 - 10

\frac{( - 4 x - 4 )}{7 x + 8}

What is the inverse of sqrt(4k^2+16k+25) ?
The inverse of sqrt(4k^2+16k+25) is (-4+sqrt(k^2-9))/2 ,-(sqrt(k^2-9)+4)/2