What is the inverse of f(x)=-(x+3)^2-5 ?

The inverse of f(x)=-(x+3)^2-5 is sqrt(-x-5)-3,-sqrt(-x-5)-3

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inverse of f(x)=-(x+3)^2-5

inverse

f (x) = - (x + 3)^{2} - 5

- x - 5 - 3, - - x - 5 - 3

Solution steps

y = - (x + 3)^{2} - 5

Replace

x

with

y

x = - (y + 3)^{2} - 5

Solve for

y, x = - (y + 3)^{2} - 5

- x - 5 - 3, - - x - 5 - 3

\frac{2 x + 8}{5 x - 1}

g (x) = \frac{x}{x - 2}

ln (2 θ + 1)

f (- 8) = \frac{x + 5}{x + 10}

\frac{3 + 5 x}{3 - x}

What is the inverse of f(x)=-(x+3)^2-5 ?
The inverse of f(x)=-(x+3)^2-5 is sqrt(-x-5)-3,-sqrt(-x-5)-3