What is the inverse of sqrt(x^2-4x)-1 ?

The inverse of sqrt(x^2-4x)-1 is 2+sqrt(x^2+2x+5),2-sqrt(x^2+2x+5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of sqrt(x^2-4x)-1

inverse

x^{2} - 4 x - 1

2 + x^{2} + 2 x + 5, 2 - x^{2} + 2 x + 5

Solution steps

y = x^{2} - 4 x - 1

Replace

x

with

y

x = y^{2} - 4 y - 1

Solve for

y, x = y^{2} - 4 y - 1

2 + x^{2} + 2 x + 5, 2 - x^{2} + 2 x + 5

f (x) = 1 + \frac{x}{30}

f (- 9) = \frac{x + 1}{x + 8}

f (x) = 800 + 55 x

g (x) = 10 x^{5} - 3

What is the inverse of sqrt(x^2-4x)-1 ?
The inverse of sqrt(x^2-4x)-1 is 2+sqrt(x^2+2x+5),2-sqrt(x^2+2x+5)