What is the inverse of (3x^2+9x-12)/(x^2+13x+36) ?

The inverse of (3x^2+9x-12)/(x^2+13x+36) is (-3-9x)/(x-3)

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inverse of (3x^2+9x-12)/(x^2+13x+36)

inverse

\frac{3 x ^{2} + 9 x - 12}{x ^{2} + 13 x + 36}

\frac{- 3 - 9 x}{x - 3}

Solution steps

y = \frac{3 x ^{2} + 9 x - 12}{x ^{2} + 13 x + 36}

Replace

x

with

y

x = \frac{3 y ^{2} + 9 y - 12}{y ^{2} + 13 y + 36}

Solve for

y, x = \frac{3 y ^{2} + 9 y - 12}{y ^{2} + 13 y + 36}

\frac{- 3 - 9 x}{x - 3}

f (x) = \frac{3 - x}{2 x + 5}

f (x) = \frac{2 x + 7}{x - 2}

f (x) = csc^{2} (x)

\frac{8}{1 - x ^{3}}

f (x) = \frac{2 x + 7}{x - 1}

What is the inverse of (3x^2+9x-12)/(x^2+13x+36) ?
The inverse of (3x^2+9x-12)/(x^2+13x+36) is (-3-9x)/(x-3)