What is the inverse of f(x)=4-sqrt(1-x^2) ?

The inverse of f(x)=4-sqrt(1-x^2) is sqrt(-x^2+8x-15),-sqrt(-x^2+8x-15)

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inverse of f(x)=4-sqrt(1-x^2)

inverse

f (x) = 4 - 1 - x^{2}

- x^{2} + 8 x - 15, - - x^{2} + 8 x - 15

Solution steps

y = 4 - 1 - x^{2}

Replace

x

with

y

x = 4 - 1 - y^{2}

Solve for

y, x = 4 - 1 - y^{2}

- x^{2} + 8 x - 15, - - x^{2} + 8 x - 15

49 + 2.3 (h - 61)

f (x) = 7^{(x - 8)} + 10

f (x) = (2.44) = 15.72 c

What is the inverse of f(x)=4-sqrt(1-x^2) ?
The inverse of f(x)=4-sqrt(1-x^2) is sqrt(-x^2+8x-15),-sqrt(-x^2+8x-15)