What is the inverse of f(x)= 1/(sqrt(x^2+10)) ?

The inverse of f(x)= 1/(sqrt(x^2+10)) is (sqrt(1-10x^2))/x ,-(sqrt(1-10x^2))/x

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inverse of f(x)= 1/(sqrt(x^2+10))

inverse

f (x) = \frac{1}{x ^{2} + 10}

\frac{1 - 10 x ^{2}}{x}, - \frac{1 - 10 x ^{2}}{x}

Solution steps

y = \frac{1}{x ^{2} + 10}

Replace

x

with

y

x = \frac{1}{y ^{2} + 10}

Solve for

y, x = \frac{1}{y ^{2} + 10}

\frac{1 - 10 x ^{2}}{x}, - \frac{1 - 10 x ^{2}}{x}

f (x) = 2000 - 4 x

f (x) = - \frac{x}{2} - \frac{1}{2}

f (x) = 5^{3 x} - 6

3^{x + 2} - 4

What is the inverse of f(x)= 1/(sqrt(x^2+10)) ?
The inverse of f(x)= 1/(sqrt(x^2+10)) is (sqrt(1-10x^2))/x ,-(sqrt(1-10x^2))/x