What is the inverse of 7/(4^3sqrt(x^2)) ?

The inverse of 7/(4^3sqrt(x^2)) is 7/(64x),-7/(64x)

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inverse of 7/(4^3sqrt(x^2))

inverse

\frac{7}{4 ^{3} x ^{2}}

\frac{7}{64 x}, - \frac{7}{64 x}

Solution steps

y = \frac{7}{4 ^{3} x ^{2}}

Replace

x

with

y

x = \frac{7}{4 ^{3} y ^{2}}

Solve for

y, x = \frac{7}{4 ^{3} y ^{2}}

\frac{7}{64 x}, - \frac{7}{64 x}

\frac{8 - 5 x}{3 + 2 x}

f (x) = 1 + 2 ln (x + 3)

f (x) = 4^{x - 1} + 1

f (x) = 5 x^{4} - 5

f (x) = e^{5 x + 3} + 5

What is the inverse of 7/(4^3sqrt(x^2)) ?
The inverse of 7/(4^3sqrt(x^2)) is 7/(64x),-7/(64x)