What is the inverse of f(x)=(1/(0.15x+1)) ?

The inverse of f(x)=(1/(0.15x+1)) is (1-x)/(0.15x)

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inverse of f(x)=(1/(0.15x+1))

inverse

f (x) = (\frac{1}{0.15 x + 1})

\frac{1 - x}{0.15 x}

Solution steps

y = \frac{1}{0.15 x + 1}

Replace

x

with

y

x = \frac{1}{0.15 y + 1}

Solve for

y, x = \frac{1}{0.15 y + 1}

\frac{1 - x}{0.15 x}

- 3 (\frac{1}{2})^{x} - 6

f (x) = - 6 (- 6 x)

\frac{6}{s ^{2} + 4}

f (x) = 3 arccos (x)

f (x) = x^{2} - 12, x \geq 0

What is the inverse of f(x)=(1/(0.15x+1)) ?
The inverse of f(x)=(1/(0.15x+1)) is (1-x)/(0.15x)