What is the inverse of h(x)=(10x)/(8x-3) ?

The inverse of h(x)=(10x)/(8x-3) is (3x)/(2(4x-5))

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inverse of h(x)=(10x)/(8x-3)

inverse

h (x) = \frac{10 x}{8 x - 3}

\frac{3 x}{2 ( 4 x - 5 )}

Solution steps

y = \frac{10 x}{8 x - 3}

Replace

x

with

y

x = \frac{10 y}{8 y - 3}

Solve for

y, x = \frac{10 y}{8 y - 3}

\frac{3 x}{2 ( 4 x - 5 )}

f (x) = \frac{4 + x ^{2}}{2}

f (x) = \frac{x}{3} + 7

12 \cdot x^{2} - 60 x + 44

f (c) = c - 8

- \frac{3}{4} x - 2

What is the inverse of h(x)=(10x)/(8x-3) ?
The inverse of h(x)=(10x)/(8x-3) is (3x)/(2(4x-5))