What is the inverse of f(x)= 4/(2x^2+6) ?

The inverse of f(x)= 4/(2x^2+6) is sqrt((2-3x)/x),-sqrt((2-3x)/x)

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inverse of f(x)= 4/(2x^2+6)

inverse

f (x) = \frac{4}{2 x ^{2} + 6}

\frac{2 - 3 x}{x}, - \frac{2 - 3 x}{x}

Solution steps

y = \frac{4}{2 x ^{2} + 6}

Replace

x

with

y

x = \frac{4}{2 y ^{2} + 6}

Solve for

y, x = \frac{4}{2 y ^{2} + 6}

\frac{2 - 3 x}{x}, - \frac{2 - 3 x}{x}

10 (3) + 14

x^{2} - 18 x

- x^{5}

f (x) = 2 (4^{x})

\frac{5 x - 1}{7 x + 6}

What is the inverse of f(x)= 4/(2x^2+6) ?
The inverse of f(x)= 4/(2x^2+6) is sqrt((2-3x)/x),-sqrt((2-3x)/x)