What is the inverse of f(x)=2^{x-3}-5,(4,7) ?

The inverse of f(x)=2^{x-3}-5,(4,7) is (ln(x+5))/(ln(2))+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2^{x-3}-5,(4,7)

inverse

f (x) = 2^{x - 3} - 5, (4, 7)

\frac{ln ( x + 5 )}{ln ( 2 )} + 3

Solution steps

y = 2^{x - 3} - 5

Replace

x

with

y

x = 2^{y - 3} - 5

Solve for

y, x = 2^{y - 3} - 5

\frac{ln ( x + 5 )}{ln ( 2 )} + 3

f (x) = ((3 \cdot x - 1))

f (x) = \frac{5 x + 7}{3 x - 5}

2^{x^{2} + 2 x}

f (x) = 7 + x - 7

\frac{7 x - 5}{11}

What is the inverse of f(x)=2^{x-3}-5,(4,7) ?
The inverse of f(x)=2^{x-3}-5,(4,7) is (ln(x+5))/(ln(2))+3