What is the inverse of (2x)/(x^2+1) ?

The inverse of (2x)/(x^2+1) is (1+sqrt(-x^2+1))/x ,(1-sqrt(-x^2+1))/x

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inverse of (2x)/(x^2+1)

inverse

\frac{2 x}{x ^{2} + 1}

\frac{1 + - x ^{2} + 1}{x}, \frac{1 - - x ^{2} + 1}{x}

Solution steps

y = \frac{2 x}{x ^{2} + 1}

Replace

x

with

y

x = \frac{2 y}{y ^{2} + 1}

Solve for

y, x = \frac{2 y}{y ^{2} + 1}

\frac{1 + - x ^{2} + 1}{x}, \frac{1 - - x ^{2} + 1}{x}

2 - e^{x + 3}

f (x) = 5^{x} + 5^{7}

f (x) = 7 + ln (x - 2)

3 x^{3} + 2

f (x) = (x^{3} - 2)^{\frac{1}{5}} + 3

What is the inverse of (2x)/(x^2+1) ?
The inverse of (2x)/(x^2+1) is (1+sqrt(-x^2+1))/x ,(1-sqrt(-x^2+1))/x