What is the inverse of f(x)=(-x^2)/(16) ?

The inverse of f(x)=(-x^2)/(16) is 4sqrt(-x),-4sqrt(-x)

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inverse of f(x)=(-x^2)/(16)

inverse

f (x) = \frac{- x ^{2}}{16}

4 - x, - 4 - x

Solution steps

y = \frac{- x ^{2}}{16}

Replace

x

with

y

x = \frac{- y ^{2}}{16}

Solve for

y, x = \frac{- y ^{2}}{16}

4 - x, - 4 - x

f (x) = \frac{4 x + 2}{3 x - 1}

\frac{x}{8} + 3

- 9.56 - 4.95 - 11.95

y = 4^{x} - 5

What is the inverse of f(x)=(-x^2)/(16) ?
The inverse of f(x)=(-x^2)/(16) is 4sqrt(-x),-4sqrt(-x)