What is the inverse of y=(-6)/(sqrt(9-x^2)) ?

The inverse of y=(-6)/(sqrt(9-x^2)) is sqrt(-(36-9x^2)/(x^2)),-sqrt(-(36-9x^2)/(x^2))

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inverse of y=(-6)/(sqrt(9-x^2))

inverse

y = \frac{- 6}{9 - x ^{2}}

- \frac{36 - 9 x ^{2}}{x ^{2}}, - - \frac{36 - 9 x ^{2}}{x ^{2}}

Solution steps

y = \frac{- 6}{9 - x ^{2}}

Replace

x

with

y

x = \frac{- 6}{9 - y ^{2}}

Solve for

y, x = \frac{- 6}{9 - y ^{2}}

- \frac{36 - 9 x ^{2}}{x ^{2}}, - - \frac{36 - 9 x ^{2}}{x ^{2}}

f (x) = (x - 3)

f (x) = \frac{x + 4}{x - 9}

f (x) = \frac{e ^{x}}{e ^{x} + 3}

f (x) = \frac{1}{x + 2} + 1

3^{x + 9}

What is the inverse of y=(-6)/(sqrt(9-x^2)) ?
The inverse of y=(-6)/(sqrt(9-x^2)) is sqrt(-(36-9x^2)/(x^2)),-sqrt(-(36-9x^2)/(x^2))